Potensregler

math $\frac = 2 \cdot {3^2} \cdot {4^{ - 5}} \cdot {6^{ - ( - 7)}} = 2 \cdot {3^2} \cdot {({2^2})^{ - 5}} \cdot {(2 \cdot 3)^7} = 2 \cdot {3^2} \cdot {2^{ - 10}} \cdot {2^7} \cdot {3^7} = {2^{1 - 10 + 7}} \cdot {3^{2 + 7}} = {2^{ - 2}} \cdot {3^9} = \underline{\underline {\frac }} $

math